3[x+3]=7[x-2]

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Solution for 3[x+3]=7[x-2] equation:


Simplifying
3[x + 3] = 7[x + -2]

Reorder the terms:
3[3 + x] = 7[x + -2]
[3 * 3 + x * 3] = 7[x + -2]
[9 + 3x] = 7[x + -2]

Reorder the terms:
9 + 3x = 7[-2 + x]
9 + 3x = [-2 * 7 + x * 7]
9 + 3x = [-14 + 7x]

Solving
9 + 3x = -14 + 7x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-7x' to each side of the equation.
9 + 3x + -7x = -14 + 7x + -7x

Combine like terms: 3x + -7x = -4x
9 + -4x = -14 + 7x + -7x

Combine like terms: 7x + -7x = 0
9 + -4x = -14 + 0
9 + -4x = -14

Add '-9' to each side of the equation.
9 + -9 + -4x = -14 + -9

Combine like terms: 9 + -9 = 0
0 + -4x = -14 + -9
-4x = -14 + -9

Combine like terms: -14 + -9 = -23
-4x = -23

Divide each side by '-4'.
x = 5.75

Simplifying
x = 5.75

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